1.2x^2+80x=930

Solution for 1.2x^2+80x=930 equation:

1.2x^2+80x=930

We move all terms to the left:

1.2x^2+80x-(930)=0

a = 1.2; b = 80; c = -930;
Δ = b2-4ac
Δ = 802-4·1.2·(-930)
Δ = 10864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10864}=\sqrt{16*679}=\sqrt{16}*\sqrt{679}=4\sqrt{679}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-4\sqrt{679}}{2*1.2}=\frac{-80-4\sqrt{679}}{2.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+4\sqrt{679}}{2*1.2}=\frac{-80+4\sqrt{679}}{2.4}
$